On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 m m H g to 640 m m H g . The depression of freezing point of benzene (in K ) upon addit

Question

On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 m m H g to 640 m m H g . The depression of freezing point of benzene (in K ) upon addition of the solute is _______ (Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g m o l - 1 and 5.12 K k g m o l - 1 , respectively)

TestHub · Accepted Answer

ΔP Ps = n solute n solvent 650 - 640 640 = 1 × 0.5 × 78 M × 39 M solute = 64 g ΔT F = k f × m ⇒ 5.12 × 0.5 × 1000 64 × 39 ΔT f = 1.0256

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