Chemistry - Liquid Solution Question with Solution | TestHub

Freezing point of diluted milk $=-0.2^{\circ }\mathrm{C}$ $$\Delta {\mathrm{T}}_{\mathrm{f}}^{\ast }=0.2^{\circ }\mathrm{C}$$ Free ring point ol pure milk $=-0.5^{\circ }\mathrm{C}$ $$\Delta {\mathrm{T}}_{\mathrm{f}}=0.5^{\circ }\mathrm{C}$$ $\frac{\Delta {\mathrm{T}}_{\mathrm{f}}}{\Delta {\mathrm{T}}_{\mathrm{f}}^{\prime }}=\frac{{\mathrm{K}}_{\mathrm{f}}\times m}{{\mathrm{K}}_{\mathrm{f}}\times m^{\prime }};m=\frac{\text{ mole of solute }}{\text{ mass of solvent }(\mathrm{kg})}$ Moles of solute are same in both samples. $$\therefore \frac{0.5}{0.2}=\frac{{\mathrm{W}}^n}{\mathrm{W}}$$ $\frac{{\mathrm{W}}^{\prime }}{\mathrm{W}}=\frac{5}{2};{\mathrm{W}}^{\prime }=\frac{5}{2}\mathrm{W}$ 2 cups of pure milk is mixed with 3 cups of water to make 5 cups of diluted milk.