Ethylene glycol is used as antifreeze to reduce freezing point of water to − 2. 4 ∘ C . What mass of antifreeze is required for 2 L water? ( K f water = 1.86 K kg / mole )

w solute = K f Δ T f × w water × M solute = 1.86 2.4 × 2 × 0.062 = 160 g [Mass of 2 L of water is 2 kg .]

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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2018

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Ethylene glycol is used as antifreeze to reduce freezing point of water to $- 2. 4^{\circ} C$ . What mass of antifreeze is required for $2 L$ water? $(K_{f}$ water $= 1.86 K kg / mole)$

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Answer:

Solution:

$w_{solute} = \frac{Δ T _{f} \times w _{water} \times M _{solute}}{K _{f}} = \frac{2.4 \times 2 \times 0.062}{1.86} = 160 g$ [Mass of $2 L$ of water is $2 kg$ .]

Stream:AIIMSSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2018

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