Chemistry - Liquid Solution Question with Solution | TestHub

$\because$ For Isotonic solution $${\pi }_1={\pi }_2\text{ i.e. }{i}_1{C}_{1}RT=i{f}_{2}RT$$ For option $(c)$ $$\begin{array}{l}{i}_1=2,i_2=3\\ C_1=0.03\\ C_2=0.02\end{array}$$ Thus, $i_1\times C_1=i_2\times C_2$ Hence, are isotonic, i.e. $$0.06=0.06$$ In all other options, $i_1\times C_1\ne i_2\times C_2$ Thus, are not isotonic.