Chemistry - Liquid Solution Question with Solution | TestHub

$\pi =\text{i C R T.}$

$10\text{.}8=\text{i}\times 0\text{.}10\times 0\text{.}082\times 298$

$\text{i}=\frac{10\text{.}8}{0\text{.}10\times 0\text{.}082\times 298}=\frac{10\text{.}8}{2.4436}$$=\frac{10\text{.}8}{2\text{.}4438}$

$= 4.42$(experimental value)

${\text{FeSO}}_4\text{.}\underset{0·1\text{M}}{{\left({\text{NH}}_4\right)}_2}{\text{SO}}_4⟶\underset{01\text{M}}{{\text{Fe}}_{\text{aq}}^{2+}}+2\underset{0·2\text{M}}{{\text{SO}}_{4\text{aq}}^{2-}}+2\underset{0·2\text{M}}{{\text{NH}}_{4\text{aq}}^{+}}$

$\mathrm{i}$(expected)$=\frac{0·5\text{M}}{0·1\text{M}}=5$