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ChemistryLiquid SolutionAbnormal Colligatiove PropertiesHard2 minPYQ_2011

ChemistryHardsingle choice

The degree of dissociation $(α)$ of a weak electrolyte, $A_{x} B_{y}$ is related to van't Hoff factor (i) by the expression:

Answer:

Solution:

$i = 1 - α + n α = 1 + α (n - 1) \frac{i - 1}{n - 1} = α A_{x} B_{y} \to x A^{+ y} + y B^{- x} n = x + y$ So $α = \frac{i - 1}{x + y - 1}$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2011

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