Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesMedium2 minQB

ChemistryMediumsingle choice

What is the approximate $OH^{-}$ ion concentration of a $0.150 M NH_{3}$ solution? $(K_{b} = 1.75 \times 1 0^{- 5})$

Answer:

Solution:

$N H_{3} + H_{2} 0 ⇌ N H_{4}^{+} + O H^{-}$

0.15(1 - $α$ ) (0.15 $α$ ) (0.15 $α$ )

$1.75 \times 1 0^{- 5} = \frac{( 0.15 α ) ( 0.15 α )}{0.15 ( 1 - α )} = 0.15 α^{2}$ ; $α = 0.011$

$[O H^{-}] = 0.15 α = 1.6 \times 1 0^{- 3}$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: QB

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