Chemistry - Ionic Equilibrium Question with Solution | TestHub

Aqueous solution of $({\mathrm{NH}}_4{)}_2{\mathrm{CO}}_3$ is Basic.

$\mathrm{pH}$ of salt of weak acid and weak base depends on ${\mathrm{K}}_{\mathrm{a}}$ and ${\mathrm{K}}_{\mathrm{b}}$ value of acid and the base forming it.

Solution is basic if

${\mathrm{K}}_{\mathrm{b}}$(weak base) >${\mathrm{K}}_{\mathrm{a}}$(weak acid).

${\mathrm{K}}_{\mathrm{a}}$(${\mathrm{HCO}}_3^{-}$)=$4.3\times {10}^{-13}$

${\mathrm{K}}_{\mathrm{b}}\left({\mathrm{NH}}_4\mathrm{OH}\right)$=$1.8\times {10}^{-5}$

${\mathrm{K}}_{\mathrm{b}}$ (Ammonium hydroxide) >${{\mathrm{K}}_{\mathrm{a}}}_{}$(Hydrogen carbonate)

∴ Hence, solution of Ammonium carbonate is basic in nature.

Hence Both Statement I and Statement II are correct.