Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesMedium2 minQB

ChemistryMediumsingle choice

What will be the pH of a solution formed by mixing $40 cm^{3}$ of 0.1 M HCl with $10 cm^{3}$ of 0.45 M NaOH ?

Answer:

Solution:

NaOH + HCl → NaCl + H₂O

Initial: 4.5 mmol 4 mmol 0 0

Final: 0.5 mmol 0 4 mmol 4 mmol

Solution is basic hence, $[O H^{-}] = \frac{0.5 mm o l}{50 m L} = 0.01 M = 1 0^{- 2} M$ .

Thus, $pO H = 2$ , So $p H = 12$ .

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: QB

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