Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumGeneral (Ostwald's Dilution Law, Degree of Ionisation)Medium2 minPYQ_2025

ChemistryMediumsingle choice

The molar solubility(s) of zirconium phosphate with molecular formula $(Zr^{4 +})_{3} (PO_{4}^{3 -})_{4}$ is given by relation :

Options:

Answer:

Solution:

$Zr_{3} (PO_{4})_{4} (s) ⇌ - 3 Zr^{+ 4} (aq) + 4 PO_{4}^{- 3} (aq) 3 s 4 s$

$K_{sp} = (3 s)^{3} (4 s)^{4} = 6912 s^{7} s = (\frac{K _{sp}}{6912})^{1/7}$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:General (Ostwald's Dilution Law, Degree of Ionisation)

⏱ 2mℹ️ Source: PYQ_2025

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