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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductEasy2 minPYQ_2021
ChemistryEasystatement

The solubility ofCdSO4in water is8.0×10-4 mol L-1. Its solubility in0.01M H2SO4solution is ___×10-6 mol L-1(Round off to the Nearest integer) (Assume that solubility is much less than0.01 M)

Answer:
64
Solution:

In pure water,

Ksp=S2=8×10-42

=64×10-8

In 0.01 M H2SO4

H2SO4(aq)x2H(aq)+x+SO42-(aq.)(x+0.01)

Ksp=x(x+0.01)

=64×10-8

x+0.010.01 M

So, x(0.01)=64×10-8

x=64×10-6M

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product
2mℹ️ Source: PYQ_2021

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