Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\mathrm{H}\mathrm{P}{\mathrm{O}}_4^{2-}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{H}}_2\mathrm{P}{\mathrm{O}}_4^{-}+{\mathrm{O}\mathrm{H}}^{-}$

$\mathrm{H}\mathrm{P}{\mathrm{O}}_4^{2-}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons \mathrm{P}{\mathrm{O}}_4^{3-}+{\mathrm{H}}_3{\mathrm{O}}^{+}$

${\mathrm{H}}_2\mathrm{P}{\mathrm{O}}_2^{-}\mathrm{ }$is a conjugate base of${\mathrm{H}}_3{\mathrm{P}\mathrm{O}}_2\mathrm{ }$(a monobasic acid) and does not give${\mathrm{H}}^{+},\mathrm{ }\mathrm{H}\mathrm{P}{\mathrm{O}}_3^{2-}$is a conjugate base of${\mathrm{H}}_2\mathrm{P}{\mathrm{O}}_3^{-}\mathrm{ }$and does not ionise further, since${\mathrm{H}}_3\mathrm{P}{\mathrm{O}}_3$is a dibasic acid.