K 1 and K 2 for oxalic acid are 6.5 × 1 0 2 - and 6.1 × 1 0 - 5 respectively. What will be [ H O - ] in a 0.01 M solution of sodium oxalate?

The hydrolysis of C 2 O 4 2 - is represented by C 2 O 4 2 - + H 2 O ⇌ H C 2 O 4 - + O H - K h = K w K 2 = 1.0 × 1 0 - 14 6.1 × 1 0 - 5 = x 2 0.01 So x = 1.28 × 1 0 - 6

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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumHydrolysis of SaltsEasy2 minPYQ_2020

ChemistryEasysingle choice

$K_{1}$ and $K_{2}$ for oxalic acid are $6.5 \times 1 0^{2 -}$ and $6.1 \times 1 0^{- 5}$ respectively. What will be $[H O^{-}]$ in a 0.01 M solution of sodium oxalate?

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Answer:

Solution:

The hydrolysis of $C_{2} O_{4}^{2 -}$ is represented by
$C_{2} O_{4}^{2 -} + H_{2} O ⇌ H C_{2} O_{4}^{-} + O H^{-}$
$K_{h} = \frac{K_{w}}{K_{2}} = \frac{1.0 \times 1 0^{- 14}}{6.1 \times 1 0^{- 5}} = \frac{x^{2}}{0.01}$
So $x = 1.28 \times 1 0^{- 6}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Hydrolysis of Salts

⏱ 2mℹ️ Source: PYQ_2020

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