Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The solubility of a sparingly soluble salt $A {(OH)}_{2}$ (mol. wt. 192.3) is $19 .23 g / litre$ at $300 K$ . The $pH$ of its saturated solution assuming 80% ionisation at $300 K$ is :

Options:

Answer:

Solution:

$S = \frac{19.23}{192.3} mol/litre = 0.1 M$
$\begin{matrix} A {(OH)}_{2} & ⇌ & A^{2 +} & + & 2 {OH}^{-} \\ 2 S \end{matrix}$
$∴ [{OH}^{-}] = \frac{0.1 \times 2 \times 80}{100} = 0.16$
$∴ pOH = 0.7958$
$∴ pH = 13.2041$

Stream:NTA_ABHYASSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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