Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesEasy2 minPYQ_2020

ChemistryEasysingle choice

If $p K_{b}$ for fluoride ion at 25 $°$ C is 10.83, the ionization constant of hydrofluoric acid in water at this temperature is

Answer:

Solution:

${pK}_{b} = 10 .83$

$- \log K_{b} = 10 .83$

$K_{b} = antilog (- 10 .83)$

$K_{b} = 1 .48 \times 10^{-11}$

$K_{a} \times K_{b} = K_{w}$
So $K_{a} = \frac{K_{w}}{K_{b}}$
$= \frac{1 0^{- 14}}{1.48 \times 1 0^{- 11}}$
$= 6.75 \times 1 0^{- 4}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2020

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