Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Three sparingly soluble salts that have same solubility products as given below

I. $A_{2} X$ II. $A X$ III. $A_{2} X_{3}$

Their solubilities in a saturated solution will be such that

Options:

Answer:

Solution:

Let $K_{s p} = 10^{- 30}$

${(10^{- 30})}^{\frac{1}{2}} = 10^{- 15}$
${(\frac{10^{- 30}}{4})}^{\frac{1}{3}} = \frac{10^{- 10}}{{(4)}^{\frac{1}{3}}}$
${(\frac{10^{- 30}}{108})}^{\frac{1}{5}} = \frac{10^{- 6}}{{(108)}^{\frac{1}{5}}}$

$S = \sqrt{K_{s p}}$ for AX
$S = {[\frac{K_{s p}}{4}]}^{1 / 3}$ for $A_{2} X$
$S = {[\frac{K_{s p}}{108}]}^{1 / 5}$ for $A_{2} X_{3}$
So $S_{III} > S_{II} > S_{I}$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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