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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesEasy2 minPYQ_2016

ChemistryEasysingle choice

Assertion : $H_{2} S$ is stronger acid than $PH_{3}$ . Reason : $S$ is more electronegative than $P$ , conjugate base $HS^{-}$ is more stable than $H_{2} P^{-}$ .

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Answer:

Solution:

$H_{2} S_{(g)} + a q ⟶ HS_{(a q)}^{-} + H_{(a q)}^{+} PH_{3 (g)} + a q ⟶ H_{2} P^{-} + H_{(a q)}^{+}$ As $S$ is more electronegative than $P$ , conjugate base $HS^{-}$ is more stable than $H_{2} P^{-}$ . Hence, $H_{2} S$ is stronger acid than $PH_{3}$ .

Stream:AIIMSSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2016

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