Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\mathrm{N}{\mathrm{H}}_4^{+}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons \mathrm{ }{\mathrm{N}\mathrm{H}}_4\mathrm{O}\mathrm{H}\mathrm{ }+\mathrm{ }{\mathrm{H}}^{+}$

${\text{K}}_{\text{eq}}=\frac{\left({\text{NH}}_4\text{OH}\right)\left[{\text{OH}}^{-}\right]\left({\text{H}}^{+}\right)}{\left({\text{H}}_2\text{O}\right)\left({\text{NH}}_4^{+}\right)\left[{\text{OH}}^{-}\right]}$

${\text{K}}_{\text{e}\text{q}}=\frac{{\text{K}}_{\text{w}}}{{\text{K}}_{\text{b}}}$

$\Rightarrow 5.5\times {10}^{-10}=\frac{{10}^{-14}}{{\text{K}}_{\text{b}}}$

${\text{K}}_{\text{b}}=\frac{{10}^{-14}}{5.5\times {10}^{-10}}=1.8\times {10}^{-5}$