The hydrogen ion concentration in 0.2 M ethanoic acid ( K a = 2 × 1 0 - 5 m o l d m - 3 ) is

For weak acid H + = K a . C = 2 × 10 - 5 × 0.2 = 2 × 10 - 3

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ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

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The hydrogen ion concentration in 0.2 M ethanoic acid $(K_{a} = 2 \times 1 0^{- 5} m o l d m^{- 3})$ is

Answer:

Solution:

For weak acid
$[H^{+}] = \sqrt{K_{a} . C}$
$= \sqrt{2 \times 10^{- 5} \times 0.2}$
$= 2 \times 10^{- 3}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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