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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesEasy2 minPYQ_2020

ChemistryEasysingle choice

For a weak electrolyte $α_{1}$ and $α_{2}$ are in ratio of 1 : 2, for a given concentration $k_{a_{1}} = 2 \times 1 0^{- 4} .$ What will be value of $k_{a_{2}}$ ?

Options:

Answer:

Solution:

$\frac{α_{1}}{α_{2}} = \sqrt{\frac{k_{a_{1}}}{k_{a_{2}}}}$
$\frac{1}{2} = \sqrt{\frac{2 \times 1 0^{- 4}}{k_{a_{2}}}}$
$\frac{1}{4} = \frac{2 \times 1 0^{- 4}}{k_{a_{2}}}$
$k_{a_{2}} = 8 \times 1 0^{- 4}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2020

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