Chemistry - Ionic Equilibrium Question with Solution | TestHub

Degree of dissociation,$\mathrm{\alpha }=\frac{14}{100}=0.14$

Concentration of maleic acid,$\mathrm{C}=0.010\text{ M}$

The equilibrium reaction is







${\mathrm{K}}_{\mathrm{a}}=\frac{{\mathrm{C}}^2{\mathrm{\alpha }}^2}{\mathrm{C}(1-\mathrm{\alpha })}=\frac{\mathrm{C}{\mathrm{\alpha }}^2}{(1-\mathrm{\alpha })}$

${\mathrm{K}}_{\mathrm{a}}=\frac{0.010\times 0.14\times 0.14}{0.86}=2.3\times 10^{-4}.$