Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesEasy2 minPYQ_2020

ChemistryEasysingle choice

At $90 ° C$ , pure water has $[H_{3} O^{+}] = 1 0^{- 6}$ mol $l i t r e^{- 1}$ . What is the value of $K_{w}$ at $90 °$ C?

Answer:

Solution:

At $90^{o} C, [H_{3} O^{+}]=[{OH}^{-}]$
$= 10^{- 6} M$
So $K_{w} = [H_{3} O^{+}] [O H^{-}]$
$= 10^{- 6} \times 10^{- 6}$
$= 10^{- 12}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2020

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