The solubility product for a salt of the type AB is 4 × 10 - 8 . What is the molarity of its saturated solution?NEET 2020 (Phase 2)

K sp for AB = s 2 = 4 × 10 - 8 ∴ Molarity of solution = solubility = K sp = 4 × 10 - 8 = 2 × 10 - 4 mol / L

Start Free Mock LoginAlready registered? Login here

Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductHard2 minPYQ_2020

ChemistryHardsingle choice

The solubility product for a salt of the type $AB$ is $4 \times 10^{- 8} .$ What is the molarity of its saturated solution?NEET 2020 (Phase 2)

Options:

Answer:

Solution:

$K_{sp}$ for $AB = s^{2} = 4 \times 10^{- 8}$
$∴$ Molarity of solution $=$ solubility $= \sqrt{K_{sp}}$
$= \sqrt{4 \times 10^{- 8}}$
$= 2 \times 10^{- 4} mol / L$

Stream:NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...