Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

If the ${pK}_{a}$ of a weak acid $HA$ is $4 .80$ and the ${pK}_{b}$ of a weak base $BOH$ is $4 .78 .$ Then, the $pH$ of an aqueous solution of the corresponding salt, $BA$ will be

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Answer:

Solution:

$BOH + HA \to B^{+} + A^{-} + H_{2} O$
$pH = \frac{1}{2} {pK}_{w} + \frac{1}{2} {pK}_{a} - \frac{1}{2} {pK}_{b}$
$= \frac{1}{2} (14 + 4.80 - 4.78) = 7.01$

Stream:NTA_ABHYASSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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