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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumHydrolysis of SaltsEasy2 minPYQ_2020

ChemistryEasysingle choice

Hydrolysis constants of two salts $K_{hA}$ and $K_{hB}$ of weak acids HA and HB are $1 0^{- 8}$ and $1 0^{- 6}$ . If the dissociation constant of third acid HC is $1 0^{- 2}$ . The order of acidic strength of three acids will be

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Answer:

Solution:

$K_{a} (H A) = \frac{K_{w}}{K_{h}}$
$= \frac{1 0^{- 14}}{1 0^{- 8}} = 1 0^{- 6}$
$K_{a} (H B) = \frac{K_{w}}{K_{h}}$
$= \frac{1 0^{- 14}}{1 0^{- 6}} = 1 0^{- 8}$
$K_{a} (H C) = 1 0^{- 2}$
As $K_{a}$ of HC > $K_{a}$ of HA > $K_{a}$ of HB so acidic strength is HC > HA > HB.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Hydrolysis of Salts

⏱ 2mℹ️ Source: PYQ_2020

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