40 ml N 10 H C l solution is mixed with 60 ml of N 20 K O H solution. The resulting mixture will be –

Number of meq of H C l = 40 × 1 10 = 4 Number of meq of K O H = 60 × 1 20 = 3 ∴ meq of H C l > meq of K O H ∴ Solution will be acidic.

Start Free Mock LoginAlready registered? Login here

Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

40 ml $\frac{N}{10} H C l$ solution is mixed with 60 ml of $\frac{N}{20} K O H$ solution. The resulting mixture will be –

Options:

Answer:

Solution:

Number of meq of $H C l = 40 \times \frac{1}{10} = 4$
Number of meq of $K O H = 60 \times \frac{1}{20} = 3$
∴ meq of $H C l$ > meq of $K O H$
∴ Solution will be acidic.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...