Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

Calculate pH at which an acid indicator HIn with concentration 0.1 M changes its colour ( $K_{a}$ for HIn $= 1 \times 1 0^{- 5}$ ).

Answer:

5.00

Solution:

Indicator equation is
$p H = p K_{I n} + \log \frac{[I n^{-}]}{[H I n]}$
Colour change takes place when $[I n^{-}] = [H I n]$
i.e., when $p H = p K_{I n} = 5$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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