Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumTitration Based ProblemsMedium2 minQB
ChemistryMediummatching list

List - I

(Mixture in solution)

List - II

(Volume of 1 M HCl used)

(P) 4 g NaOH + 8.4 g NaHCO3

(1) At phenolphthalein end point = 50 ml

(Q) 2 g NaOH + 5.3 g Na2CO3

(2) At methyl orange end point after phenolphthalein end point = 50 ml

(R) 10.6 g Ba2CO3

(3) At phenolphthalein end point = 100 ml

(S) 5.3 g Na2CO3 + 4.2 g NaHCO3

(4) At methyl orange end point after phenolphthalein end point = 100 ml

 

(5) At methyl orange end point = 100 ml (no phenolphthalein colour change)

Options:

Answer:
B
Solution:

P 3: Phenolphthalein (Ph) estimates complete NaOH (0.1 mol); thus, .

Q 2: Methyl orange (MeO) after Ph estimates NaHCO₃ produced from Na₂CO₃ (0.05 mol); thus, .

R 4: For 0.1 mol Na₂CO₃, the volume needed to convert it from NaHCO₃ to CO₂ (after Ph) is .

S 1: Ph estimates half of Na₂CO₃ (0.05 mol) converting to NaHCO₃; thus, .

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Titration Based Problems
2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...