Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasynumerical

In 1 L saturated solution ofAgClKspAgCl=1.6×10-10, 0.1 mol ofCuCl KspCuCl=1.0×10-6is added. The resultant concentration ofAg+in the solution is1.6×10-x. The value of "x" is

Answer:
7.00
Solution:

Let the solubility ofAgClisxmollitre-1

AgClAg+x+Cl-x

And that ofCuClisymollitre-1

CuClCu+y+Cl-y

KspofAgCl=Ag+Cl-1

1.6×10-10=xx+y...(i)

SimilarlyKspofCuCl=Cu+Cl-

1.6×10-6=yx+y...(ii)

On solving (i) and (ii)

Ag+=1.6×10-7

x=7

Stream:NTA_ABHYASSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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