The molar solubility of CaF 2 ( K sp = 5.3 × 1 0 − 11 ) in 0.1 M solution of NaF will beNEET 2019 (Odisha)

Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductMedium2 minPYQ_2019

ChemistryMediumsingle choice

The molar solubility of $CaF_{2}$ $(K_{sp} = 5.3 \times 1 0^{- 11})$ in $0.1 M$ solution of $NaF$ will beNEET 2019 (Odisha)

Answer:

Solution:

Let the solubility of $CaF_{2}$ in $0.1 M NaF$ is ' $S$ ' $mol L^{- 1}$

Stream:NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2019

Loading discussions...