Chemistry - Ionic Equilibrium Question with Solution | TestHub

${\left({\mathrm{K}}_{\mathrm{sp}}\right)}_{{\mathrm{PbCl}}_2}=3.2\times 10^{-8}=32\times 10^{-9}$ ${\mathrm{PbCl}}_2\rightleftharpoons \underset{\mathrm{s}}{{\mathrm{Pb}}^{2+}}+\underset{2\mathrm{s}}{2{\mathrm{Cl}}^{-}}$ ${\mathrm{K}}_{\mathrm{sp}}=\left[{\mathrm{Pb}}^{2+}\right]{\left[{\mathrm{Cl}}^{-}\right]}^2$ ${\mathrm{K}}_{\mathrm{sp}}=4{\mathrm{s}}^3=32\times 10^{-9}$ ${\mathrm{s}}^3=8\times 10^{-9}$ $\mathrm{s}=2\times 10^{-3}\mathrm{M}$ $\frac{\mathrm{w}}{\mathrm{M}.\mathrm{W}.}\times \frac{1}{{\mathrm{V}}_{\mathrm{L}}}=2\times 10^{-3}$ $\frac{0.1}{278}\times \frac{1}{{\mathrm{V}}_{\mathrm{L}}}=2\times 10^{-3}$ ${\mathrm{V}}_{\mathrm{L}}=\frac{0.1\times 1000}{278\times 2}=0.18\mathrm{L}$