Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesMedium2 minPYQ_2017

ChemistryMediumsingle choice

Calculate the overall complex dissociation equilibrium constant for the $[Cu (NH_{3})_{4}]^{2 +}$ ions, given that stability constant $(β_{4})$ for this complex is $2.1 \times 1 0^{13}$ .

Options:

Answer:

Solution:

Dissociation constant is the reciprocal of the stability constant $(β = 1/ K)$ . Overall complex dissociation equilibrium constant, $K = \frac{1}{β _{4}} = \frac{1}{2.1 \times 1 0 ^{13}} = 4.76 \times 1 0^{- 14}$

Stream:AIIMSSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2017

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