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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumBuffer solutionMedium2 minQB

ChemistryMediumsingle choice

The $pK_{b}$ of cyanide ion is 4.7. The pH of a solution prepared by mixing 2.5 moles of KCN and 2.5 moles of HCN in water and making total volume upto 500 ml is

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Answer:

Solution:

The above solution is an acidic buffer solution, and $[S a lt] = [A c i d]$ .

Therefore, $p H = p K_{a} + lo g \frac{[ S a lt ]}{[ A c i d ]}$

or $p H = p K_{a}$ .

$p K_{a}$ of HCN = $14 - p K_{b} = 14 - 4.7 = 9.3$ .

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Buffer solution

⏱ 2mℹ️ Source: QB

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