Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductMedium2 minPYQ_2010

ChemistryMediumsingle choice

The $K_{sp}$ of $CuS, Ag_{2} S$ and $HgS$ are $1 0^{- 31}, 1 0^{- 44}$ and $1 0^{- 54}$ respectively. The solubility of these sulphides are in the order :

Options:

Answer:

Solution:

For CuS, solubility $= (1 0^{- 31})^{1/2}$ ; $For Ag_{2} S = (\frac{K _{sp}}{4})^{\frac{1}{3}} = (\frac{1 0 ^{- 44}}{4})^{\frac{1}{3}} and for HgS = (1 0^{- 54})^{\frac{1}{2}}$

Stream:BITSATSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2010

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