Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesHard2 minPYQ_2016

ChemistryHardsingle choice

The percentage of pyridine $(C_{5} H_{5} N)$ that forms pyridinium ion $(C_{5} H_{5} N^{+} H)$ in a $0.10 M$ aqueous pyridine solution $(K_{b} for C_{5} H_{5} N = 1 .7 \times 10^{- 9})$ isNEET 2016 (Phase 2)

Options:

Answer:

Solution:

$\begin{matrix} C_{5} H_{5} N + H_{2} O & ⇌ & C_{5} H_{5} N^{\oplus} H & + & {OH}^{⊖} \\ t = 0 & C \\ t = eq & C (1 - α) & C α & C α \end{matrix}$

$∴ K_{b} = \frac{C α^{2}}{1 - α} \approx C α^{2}$

$∴ α = \sqrt{\frac{K_{b}}{C}} = \sqrt{\frac{1.7 \times 10^{- 9}}{0.1}}$

$= 1.3 \times 1 0^{- 4}$

$∴ % α = 1.3 \times 10^{- 4} \times 100 = 0.013 %$

Stream:NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2016

Doubts & Discussion

Loading discussions...