The solubility product of different sparingly soluble salts are
$1 .$ $X Y = 4 \times 1 0^{- 20}$
$2 .$ $X_{2} Y = 3.2 \times 1 0^{- 11}$
$3 .$ $X Y_{3} = 2.7 \times 1 0^{- 31}$
The increasing order of solubility is

Question

The solubility product of different sparingly soluble salts are 1 . X Y = 4 × 1 0 - 20 2 . X 2 Y = 3.2 × 1 0 - 11 3 . X Y 3 = 2.7 × 1 0 - 31 The increasing order of solubility is

TestHub · Accepted Answer

S ( X Y ) = K s p = 4 × 1 0 - 20 = 2 × 1 0 - 10 S ( X 2 Y ) = K s p 4 1 / 3 = 3.2 × 1 0 - 11 4 1 / 3 = 2 × 1 0 - 4 S ( X 3 Y ) = K s p 27 1 / 4 = 2.7 × 1 0 - 31 27 1 / 4 = 1 0 - 8 Hence, the solubility order is X Y < X 3 Y < X 2 Y .

Chemistry - Ionic Equilibrium Question with Solution | TestHub

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