Chemistry - Ionic Equilibrium Question with Solution | TestHub

$\mathrm{pH}=1=-\log \left[{\mathrm{H}}^{+}\right]$

$\left[{\mathrm{H}}^{+}\right]={10}^{-1} \mathrm{M}$

$\mathrm{Final} \mathrm{pH}=2; \left[{\mathrm{H}}^{+}\right]={10}^{-2} \mathrm{M}$

${\mathrm{M}}_1{\mathrm{V}}_1={\mathrm{M}}_2{\mathrm{V}}_2$

$(0.1 \mathrm{M}\times 1 \mathrm{Litre})=(0.01) {\mathrm{V}}_2$

${\mathrm{V}}_2=10 \mathrm{L}$

Final volume$= 10 \mathrm{L}$

Water added$=10-1=9 \mathrm{L}$.