Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesEasy2 minPYQ_2023

ChemistryEasystatement

An analyst wants to convert $1 L HCl$ of $pH = 1$ to a solution of $HCl$ of $pH = 2$ . The volume of water needed to do this dilution is _____ $mL$ . (Nearest integer)

Answer:

9000

Solution:

The concentration of $H^{+}$ or say $HCl$ in both the given solution is $10^{- 1}$ and $10^{- 2}$ mole $L^{- 1}$ respectively.

For the given amount of $HCl$ the concentration depends over dilution hence

$M_{1} V_{1} = M_{2} V_{2} \frac{M_{1}}{M_{2}} = \frac{V_{2}}{V_{1}}$

$\frac{10^{- 1}}{10^{- 2}} = \frac{V_{2}}{1 L}$

$V_{2} = 10 L = 10000 mL$

$∆ V = 10000 - 1000 mL = 9000 mL$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: PYQ_2023

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