Chemistry - Ionic Equilibrium Question with Solution | TestHub

According to Henderson's equation, $$\begin{array}{rl}& \mathrm{pH}=\mathrm{p}{K}_a+\log \frac{[\text{ salt }]}{[\text{ acid }]}\\ & {\mathrm{CH}}_3\mathrm{COOH}+\mathrm{NaOH}\to {\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{H}}_2\mathrm{O}\end{array}$$ Putting the values, we get : $$\begin{array}{rl}\mathrm{pH}& =4.57+\log \frac{0.10}{0.03}\\ \Rightarrow \mathrm{pH}& =5.09\end{array}$$