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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumBuffer solutionEasy2 minPYQ_2020

ChemistryEasysingle choice

${CH}_{3} {NH}_{2} (0.12 mole, {pK}_{b} = 3.3)$ is added to $0.08$ $m o l e s$ of $H C l$ and the solution is diluted to one litre, resulting $p H$ of solution is:

Options:

Answer:

Solution:

$p O H = p K_{b} + l o g \frac{[C H_{3} N H_{3}^{+}]}{[(C H_{3} N H_{2})]}$
$= 3.3 + l o g \frac{0.08}{0.04} = 3.6$
$∴ p H = 10.4$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Buffer solution

⏱ 2mℹ️ Source: PYQ_2020

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