Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasProblems related with container/piston/SPMMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
A glass tube AD of uniform cross-section of length 56 cm contains two columns of air (assume ideal behaviour) AB and CD, separated by a column of mercury (BC) of length 8 cm. When the tube is horizontal, AB = 20 cm and CD = 28 cm. When the tube is held vertically with the end 'A' up, the mercury column moves down 10 cm.
What will be the length of the gas column AB when the tube is held vertically with the end D up?
Options:
Answer:
A
Solution:
With D up, mercury moves toward A by x: AB = 20-x, CD = 28+x. PAB' = 9 × 20/(20-x) = PCD' + 8 = 9 × 28/(28+x) + 8. Solving gives x = 8 cm (PAB' = 15, PCD' = 7 cm Hg), so AB = 12 cm. Hence (a).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM
⏱ 2mℹ️ Source: QB
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