The mean free path of a gas is 7.0 × 1 0 − 8 m at 2 7 ∘ C and 1.0 atm. Find its mean free path at 17 7 ∘ C and 0.6 atm, in units of 1 0 − 8 m, correct to one decimal place (diameter of the molecule un

Question

The mean free path of a gas is 7.0 × 1 0 − 8 m at 2 7 ∘ C and 1.0 atm. Find its mean free path at 17 7 ∘ C and 0.6 atm, in units of 1 0 − 8 m, correct to one decimal place (diameter of the molecule unchanged).

TestHub · Accepted Answer

λ = k T / ( 2 ​ π σ 2 P ) is proportional to T/P. T 2 ​ / T 1 ​ = 450/300 = 1.5 and P 1 ​ / P 2 ​ = 1.0/0.6 . λ 2 ​ / λ 1 ​ = 1.5/0.6 = 2.5 . λ 2 ​ = 2.5 × 7.0 × 1 0 − 8 = 17.5 × 1 0 − 8 m. Answer: 17.5.

Chemistry - Ideal Gas Question with Solution | TestHub

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