Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasIdeal Gas Equation & problemsMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
Equal masses (W gram each) of three non-reacting gases X,Y and Z were mixed in sealed rigid container and total pressure at given temperature ‘T’ was found to be ‘P’ atmosphere. Now ‘2W’ grams of X is further added to same container and temperature was raised to ‘2T’. At ‘2T’ temperature, new pressure was found to be ‘4P’ atmosphere. Now ‘3W’ gram of Y was added further and temperature was raised to ‘4T’, new pressure was found to be ‘12P’
Based on above information, lightest and heaviest gases are respectively.
Options:
Answer:
B
Solution:
T......(1)
.........(2)
.........(3)
Solving (1), (2) and (3)
and
Initial masses are same,
Now,
For
For
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems
⏱ 2mℹ️ Source: QB
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