The temperature of a gas at pressure P and volume V is 2 7 ∘ C . Keeping its volume constant, if its temperature is raised to 92 7 ∘ C , then its pressure will be

T 1 P 1 V 1 = T 2 P 2 V 2 300 P × V = 200 P 2 × V So, P 2 = 4 P

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ChemistryIdeal GasIdeal Gas Equation & problemsMedium2 minQB

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The temperature of a gas at pressure P and volume V is $2 7^{\circ} C$ . Keeping its volume constant, if its temperature is raised to $92 7^{\circ} C$ , then its pressure will be

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Answer:

Solution:

$\frac{P _{1} V _{1}}{T _{1}} = \frac{P _{2} V _{2}}{T _{2}}$

$\frac{P \times V}{300} = \frac{P _{2} \times V}{200}$

So, $P_{2} = 4 P$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

⏱ 2mℹ️ Source: QB

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