Two identical containers, each of volume V o , are joined by a small pipe of negligible volume. The containers contain identical gases at temperature T o and pressure P o . One container is heated to

Question

Two identical containers, each of volume V o , are joined by a small pipe of negligible volume. The containers contain identical gases at temperature T o and pressure P o . One container is heated to temperature 2T o while maintaining the other at the same temperature, T o . The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T o , then

TestHub · Accepted Answer

Total moles are conserved: initially 2·P o V o /RT o . After heating, with common pressure P, total moles = PV o /RT o + PV o /(2RT o ) = (3/2)(PV o /RT o ). Equating: (3/2)PV o /RT o = 2P o V o /RT o , so P = 4P o /3. Moles in the hot container: n = PV o /(2RT o ) = (4P o /3)V o /(2RT o ) = 2P o V o /3RT o . Hence (b) and (c).

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