Chemistry - Ideal Gas Question with Solution | TestHub

(A) At constant $T,n$: $PV=constant\Rightarrow \frac{1}{V}\propto P$, so the graph is a straight line → R.

(B) At constant $P,n$: $V\propto T\Rightarrow \frac{V}{T}=constant$, so the graph is a horizontal line (constant) → S.

(C) $\log P=-\log V+constant$, hence a straight line with negative slope → P.

(D) At constant $T,n$: $V\propto \frac{1}{P}\Rightarrow V\propto \sqrt{\frac{1}{P^2}}$, giving the curved increasing graph→ Q.

Final Answer: $\boxed{A\to R,B\to S,C\to P,D\to Q}$