An unspecified quantity of an ideal gas was at initial pressure of 5 atm and temperature of 303 K. The gas is expanded at 303 K until the volume has increased by 60% of the initial value. Next, the qu

Question

An unspecified quantity of an ideal gas was at initial pressure of 5 atm and temperature of 303 K. The gas is expanded at 303 K until the volume has increased by 60% of the initial value. Next, the quantity of the gas in the vessel is increased by 20% of the initial value while the volume is maintained constant. Finally, the temperature is adjusted at constant volume until the gas pressure is again 5 atm. What is the final temperature, in kelvin?

Answer:

404.00

Solution:

Step 1 (isothermal, V → 1.6V): P = 5/1.6 atm.

Step 2 (constant V, n → 1.2n): P = (5/1.6) × 1.2 = 3.75 atm at 303 K.

Step 3 (constant V, heat until P = 5 atm): T = 303 × 5/3.75 = 404 K ⇒ 0404.

TestHub · Accepted Answer

Step 1 (isothermal, V → 1.6V): P = 5/1.6 atm. Step 2 (constant V, n → 1.2n): P = (5/1.6) × 1.2 = 3.75 atm at 303 K. Step 3 (constant V, heat until P = 5 atm): T = 303 × 5/3.75 = 404 K ⇒ 0404.

Chemistry - Ideal Gas Question with Solution | TestHub

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