Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasProblems related with container/piston/SPMHard2 minQB
ChemistryHardsingle choice
Passage / Comprehension
A U-shaped tube partly filled with mercury is taken as shown in the figure. The cross-section area of the closed arm is A cm² and that of the open arm is 3A cm²; initially the mercury level in the open arm stands 76 cm higher than in the closed arm. A pin hole is now made at the top of the closed arm and the trapped gas starts leaking out. The leak rate -dP/dt is directly proportional to the pressure of the remaining gas above mercury, the proportionality constant being K s⁻¹.
What will be the decrease in level of mercury in the open arm at any time, t?
Options:
Answer:
A
Solution:
From Q27, y = x/3 with x = 114(1 - e-kt) cm, so y = 38(1 - e-kt) cm. Hence Ans (a).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM
⏱ 2mℹ️ Source: QB
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