A sealed rigid vessel of 10 L contains 2 mol of argon at 300 K. The gas is heated until the u r m s of its atoms doubles, and then half of the gas is vented at that temperature. The final pressure i

Question

A sealed rigid vessel of 10 L contains 2 mol of argon at 300 K. The gas is heated until the u r m s ​ of its atoms doubles, and then half of the gas is vented at that temperature. The final pressure in the vessel is (R = 0.082 L atm/mol K)

TestHub · Accepted Answer

u r m s ​ is proportional to T ​ , so doubling u r m s ​ needs T to become 4 times: T = 1200 K. Half of the 2 mol is vented, leaving 1 mol at 1200 K in 10 L. P = n RT / V = 1 × 0.082 × 1200/10 = 9.84 atm. Without the venting P = 19.68 atm; with T only doubled (600 K) it would be 4.92 atm. Answer: (C).

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