Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasProblems related with container/piston/SPMMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
A U-shaped tube partly filled with mercury is taken as shown in the figure. The cross-section area of the closed arm is A cm² and that of the open arm is 3A cm²; initially the mercury level in the open arm stands 76 cm higher than in the closed arm. A pin hole is now made at the top of the closed arm and the trapped gas starts leaking out. The leak rate -dP/dt is directly proportional to the pressure of the remaining gas above mercury, the proportionality constant being K s⁻¹.
What will be the expression for the pressure of gas above mercury in the closed arm at any time, t?
Options:
Answer:
B
Solution:
Initially P₀ = 76 + 76 = 152 cm Hg = 2 atm. The leak law -dP/dt = kP integrates to P = P₀e-kt = 2e-kt atm. Hence Ans (b).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Problems related with container/piston/SPM
⏱ 2mℹ️ Source: QB
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